Respuesta :
0.1636M is the concentration of ammonium ions and sulphate ions in the final solution.
What do you mean by the solution ?
A solution is a homogeneous mixture of two or more substances. A solution may exist in any phase . A solution consists of a solute and a solvent.
To calculate the concentration of ammonium ions and sulphate ions in the final solution -
Ammonium sulphate formula is-------------- (NH4)2SO4
Its gram molecular weight is---------------------132g
According to the question 10.8g. of ammonium sulphate is mixed in 100ml water
Hence,
molarity of the solution=(weight of the solute / its molecular weight)×1/volume of the solution in liter
Hence,
M = (10.8/132) ×1000/100 moles/liter
= 0.818M
Hence the molarity of the ammonium sulphate stock solution is 0.818M
Let it be M1 .
From this now take 10 ml
Let it be -------------- V1.
So M1 = 0.818 M
V1 = 10ml
It is added to 50ml water. Let it be V2.
We should find M2.
As we know the relation:
M1V1= M2V2
M2 = M1V1/V2
= 0.818 M × 10 ml / 50ml
= 0.1636M
Hence , 0.1636M is the concentration of ammonium ions and sulphate ions in the final solution.
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