A gas sample has a volume of 126ml at 58.0°C then the volume of the gas at 118°C is 148.8 ml .
Calculation ,
Formula used : [tex]V_{1} /V_{2} =T_{1} /T_{2}[/tex]
Where , V is volume and T is temperature
Given initial Volume of gas sample [tex]V_{1}[/tex] = 126 ml
Final volume of gas sample [tex]V_{2}[/tex] = ?
Initial temperature of gas sample [tex]T_{1}[/tex] = 58.0°C = 58.0 + 273 = 331 K
Final temperature of gas sample [tex]T_{2}[/tex] = 118°C = 118 + 273 = 391 K
Putting the value of initial volume , Initial temperature and Final temperature in equation ( i ) we get
126ml / [tex]V_{2}[/tex] = 331 K/391 K
[tex]V_{2}[/tex] = 126ml × 391 K/ 331 K = 148.8 ml = 0.148 L
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