Respuesta :
The electron configuration that belongs to the atom with the lowest first ionization energy is 3s1.
The electron configuration serves to characterize an atom's ground state orbitals, but it may also be used to depict an atom that has charged into a cation and anion through making up for any lost or gained electrons in the orbitals after it.
The quantity of protons inside the atomic nuclei of sodium atoms gives the element an atomic number of 11. In addition, the neutral sodium atom contains 11 electrons. A neutral sodium atom has the electron configuration[tex]1s^{2} 2s^{2} 2p^{6} 3s^{1}[/tex].
Therefore, the electron configuration that belongs to the atom with the lowest first ionization energy is [tex]3s^{1}[/tex].
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