contestada

The molar heat of fusion of gold is 12.550 kj mol–1. at its melting point, how much mass of melted gold must solidify to release 235.0 kj of energy? use q equals n delta h.. 18.73 g 222.5 g 2,949.3 g 3,688.3 g

Respuesta :

The total heat released, Q, equals the number of moles, n, times molar heat of fusion, Hf. this is Q = n [tex]*[/tex] Hf.

substituting the values in the above equation we get

mass = 3688.3 g

Therefore, the correct answer is option d) 3688.3 g.

What is the molar heat of fusion?

The molar heat of fusion of a substance exists as the heat soaked by one mole of that substance as it exists transformed from a solid to a liquid. Since the melting of any substance absorbs heat, it observes that the freezing of any substance emits heat.

The total heat released, Q, equals the number of moles, n, times molar heat of fusion, Hf then Q = n [tex]*[/tex] Hf.

Where Q is the total heat

n be the number of moles

Hf is the molar heat of fusion.

Q = n [tex]*[/tex] Hf.

simplifying the above equation, we get

n = Q/Hf

= 235.0 kJ / 12.55 kJ/mol = 18.72 mol.

Atomic mass of Au = 197 g/mol

⇒ mass = 18.73 mol [tex]*[/tex] 197 g/mol

= 3688.3 grams.

Therefore, the correct answer is option d) 3688.3 g.

To learn more about the molar heat of fusion refer to:

https://brainly.com/question/3480154

#SPJ4