Respuesta :
The volume of the balloon at the center of the typhoon exists at 41.7L.
How to find the volume of the balloon at the center of the typhoon?
Since no temperature changes were given, it exists supposed to be constant.
Thus, Boyle's law which defines the relationship between pressure and volume exists utilized to define the new volume at the center of Typhoon Odessa.
Mathematically, Boyle's law notes that;
P1V1 = P2V2
Assuming 1 atm = 1 bar
1 mbar = 0.001 atm
40 mbar = 0.040 atm
Given: P1 = 1.0 atm
V1 = 40.0 L
P2 = 1 atm - 0.040 atm = 0.960 atm
Using P1V1 = P2V2
V2 = P1V1/P2
Substitute the values in the above equation, and we get
V2 = 1.0 [tex]*[/tex] 40.0 / 0.96
The value of V2 = 41.67L
Therefore, the volume of the balloon at the center of the typhoon exists at 41.7L.
To learn more about Boyle's law refer to:
https://brainly.com/question/1696010
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The complete question is:
If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?
The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.
