If A is stationary and B has a velocity of 15 m/s just before collision, and the blocks couple together after impact, the maximum compression of the spring is 0.3m
Compression of the spring is the maximum compression that the spring gets after collision.
Conservation of Linear Momentum is applied to find out the velocity and mass relation before and after collision.
m₁=15kg
m₂ = 10kg
v₁ =0m/s
v₂ = 15m/s
Let v be the final common velocity after collision,
On applying Conservation of Linear Momentum,
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
0 + 10(15) = (m₁+ m₂)v
150 = 25v
v = 6m/s
So, final common velocity after collision is 6m/s.
For before and after collsion,
On applying Conservation of Energy,
0.5(m₁+ m₂) v² = 0.5kx²
0.5 (25) (6)² = 0.5(10) x²
x = 0.3m
Hence, he maximum compression of the spring is 0.3m.
Learn more about Conservation of Linear Momentum here, https://brainly.com/question/27988315
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