Respuesta :
The answer is- EMF of cell = 0.096 V.
Nernst equation: EMF of a cell is the cell potential and Nernst equation is used to calculate the EMF of a cell.
Explain Nernst equation.
- According to Nernst equation:
[tex]\[{{\rm{E}}_{{\rm{cell}}}}{\rm{\; = }}{{\rm{E}}^{\rm{0}}}{\rm{\;- }}\left[ {\frac{{0.0591}}{{\rm{n}}}} \right]{\rm{ log Q}}\][/tex]
Where,
Ecell = EMF of the cell
E0 = Standard EMF under standard conditions
n = number of electrons transferred in the redox reaction
Q = reaction quotient
- Now, the given reaction is-
[tex]Pb + 2H^+[/tex]→[tex]Pb^2^+ + H_2[/tex]
- The Nernst equation for the given reaction is-[tex]Ecell = E_0 + \frac{0.0591}{n} log \frac{pH_2 * [Pb^2^+]}{[H^+]^2}[/tex]
- Putting all the data, emf of the cell is-
E0 = 0.13 V
[tex]Ecell = 0.13 V - [\frac{0.0591}{2}] log \frac{(1.0 *0.11) }{(0.087)^2} \\ = 0.13V - 0.034= 0.096\ V[/tex]
- Hence, the EMF of the given cell 0.096 V.
To learn more about EMF and Nernst equation, visit:
https://brainly.com/question/21601855
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