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Points P, Q, R, and S are collinear. Point W is between P and R, R is between Q and S, and PQ=RS. If PS=26 and PR=22, what is the value of QR?

Respuesta :

The points P, Q, R, and S exist collinear.

Point W exists between P and R, R exists between Q and S, and

PQ = RS then the value of PQ = RS = 4 and QR = 18.

How to find the value of QR?

Given:

Points P, Q, R, and S exist collinear.

Point W exists between P and R, R exists between Q and S, and

PQ = RS

PR = PQ+QR

QS = QR + RS

PS = PR + RS

The given parameters are:

PS = 26

PR = 22

PQ = RS

Substitute the above values in PS = PR + RS

26 = 22 + RS

Solve for RS

RS = 26 - 22

RS = 4

This means that:

PQ = RS = 4

Substitute 4 for PQ in PR = PQ + QR

PR = 4 + R

Substitute PR = 22 in PR = 4 + QR

22 = 4 + QR

Solve for QR

QR = 22 - 4

QR = 18

Therefore, the value of QR exists 18.

To learn more about the values refer to:

https://brainly.com/question/17833332

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