The freezing point depression is 2.1 °c.
What is freezing point?
The freezing point is the point that a liquid is converted to solid. Now we know that the freezing point is a colligative property.
Number of moles of glucose = 10.0g /180 g/mol =0.056 moles
Mass of water = 50.0g or 0.05 Kg
Molality of the solute = 0.056 moles/ 0.05 Kg = 1.12 m
The freezing point depression is obtained from;
ΔT = K m i
ΔT = 1.86°c/m * 1.12 m * 1
ΔT = 2.1 °c
Learn more about freezing point depression:https://brainly.com/question/2292439
#SPJ1
