Calculate the volume in milliliters of a M nickel(II) chloride solution that contains of nickel(II) chloride . Round your answer to significant digits.

Respuesta :

190 milliliters is the volume of a 0.92M nickel(II) chloride solution that contains 175 mmol of nickel(II) chloride (NiCI₂).

What is Molarity ?

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Moles of nickel(II) chloride = 175 mmol

Molarity of the nickel(II) chloride = 0.92 M

Convert mmol into mol

1 milimol = 0.001 mol

175 mmol = 0.175 mol

Now put the value in above formula to find the volume of solution

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

[tex]0.92\ M = \frac{0.175\ mol}{\text{Volume of solution}}[/tex]

Volume of solution = [tex]\frac{0.175\ mol}{0.92\ M}[/tex]

Volume of solution = 0.1902 L

Convert L into mL

1 L = 1000 mL

0.1902 L = 0.1902 × 1000 mL

              =  190.2 mL

              ≈ 190 mL

Thus from the above conclusion we can say that 190 milliliters is the volume of a 0.92M nickel(II) chloride solution that contains 175 mmol of nickel(II) chloride (NiCI₂).

Learn more about the Molarity here: https://brainly.com/question/26873446

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Question: Calculate the volume in milliliters of a 0.92M nickel(II) chloride solution that contains 175 mmol of nickel(II) chloride (NiCI₂). Round your answer to significant digits.