Respuesta :
The resonant frequency will decrease.
The natural frequency of an object, where it typically vibrates with a greater amplitude, is another way to describe the resonant frequency.
The formula for time period of pendulum(T) is
T= 2π[tex]\sqrt{} \frac{l}{g}[/tex] where,
l= length of pendulum
g = acceleration due to gravity
So, T is inversely proportional to the square root of g(√g)
It means as the value of g decreases, time period of pendulum increases and vice versa.
As it is given, value of g is less on moon than on earth and it is approx. 6 times less than that of earth.
That's why time period of oscillation of pendulum increases.
Now, as we know that time period is inversely proportional to the frequency.
So as the time period of pendulum on the moon increases, its resonant frequency decreases.
Hence, If we take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will decrease.
Learn more about pendulum here https://brainly.com/question/8168512
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