SEVEN TIMES THE SUM OF THREE CONSECUTIVE EVEN INTEGERS IS 140 MORE THAN ELEVEN TIMES THE
MIDDLE INTEGER. FIND THE INTEGERS

Respuesta :

The integers are 12,14 and 16

How to determine the integers?

Consecutive even integers are represented as:

x, x + 2 and x + 4

So, the statement is represented as:

7 * (x + x + 2 + x +4) = 140 + 11 * (x + 2)

Evaluate the like terms

7 * (3x + 6) = 140 + 11 * (x + 2)

Open the brackets

21x + 42 = 140 + 11x + 22

Collect the like terms

21x -11x =

Evaluate

10x = 120

Divide by 10

x = 12

So, we have

x + 2 = 14

x + 4 = 16

Hence, the integers are 12,14 and 16

Read more about consecutive numbers at:

https://brainly.com/question/10853762

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