The frequency is 94.2 Hz
We are given the energy of a photon = 6.24x10-29 kJ
We are asked to find the frequency (ν),
We use the equation E = hν where E is energy, h is Planck's constant and ν is the frequency
The quantity of events per unit of time that occur when an event repeats itself at regularly spaced intervals is known as its frequency.
6.24x10-29 kJ = 6.626x10-34 J-sec * ν
ν = 6.24x10-29 kJ x 1000 J/kJ / 6.626x10-34 Jsec
ν = 6.24x10-26 J / 6.626x10-34 Jsec
ν = 0.942x108 s-1 = 9.42x107 s-1 = 9.42x107 Hz
9.42x107 Hz x 1 MHz/106 Hz = 94.2 MHz
Hence the frequency is 94.2MHz
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