A team of 3 boys and 3 girls be selected from 5 boys and 4 girls in 40 ways
How to determine the number of ways?
The selections are given as:
3 boys from 5 boys
3 girls from 4 girls
Each selection is calculated using:
[tex]^nC_r = \frac{n!}{(n- r)!r!}[/tex]
So, we have:
[tex]Ways = ^5C_3 * ^4C_3[/tex]
Apply the combination formula
[tex]Ways = \frac{5!}{2!3!} * \frac{4!}{1!3!}[/tex]
Expand
[tex]Ways = \frac{5 * 4 * 3!}{2 * 3!} * \frac{4 * 3!}{1 * 3!}[/tex]
Simplify
Ways = 5 * 2 * 4
Evaluate
Ways =40
Hence, the number of ways is 40
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