15. Container A holds twice as much as
container B, and container C holds as much
as A and B put together. If we start with A
and B full, and C empty, and pour half the
contents of A and a third of the contents of
B into container C, what fraction of C’s
capacity will be filled?

Respuesta :

The fraction of C’s capacity that will be filled is determined as 4/9.

Fraction of C's capacity filled

A = 2B

C = A + B

C = 2B + B

C = 3B

When half the contents of A and a third of the contents of B into container C.

C = (1/2)A + (1/3)B

C = (1/2)(2B) + (1/3)B

C = B + (1/3)B

C = (4/3)B

Fraction of C filled;

3B(x) =  (4/3)B

3x = 4/3

9x = 4

x = 4/9

Thus, the fraction of C’s capacity that will be filled is determined as 4/9.

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