When aqueous solutions of sodium phosphate and lead(II) nitrate are combined, solid lead(II) phosphate and a solution of sodium nitrate are formed. The net ionic equation for this reaction is:

Respuesta :

2 Na3PO4 (aq) + 3 Pb(NO3)2 (aq) --> 2 Pb3(PO4)2 (s) + 6 NaNO3 (aq)

The total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation 6 Na+ (aq) + 2 PO43-(aq) + 3 Pb2+ (aq) + 6 NO3- (aq) --> 2 Pb3(PO4)2 (s) + 6 Na+ (aq) + 6 NO3- (aq)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

3 Pb2+ (aq) + 2 PO43- (aq) -> 2 Pb3(PO4)2 (s)

Answer:

2+ 3 3 Pb (aq) + 2 PO4 (aq) -> 2 Pb3(PO4)2 (5)

Lead(II) nitrate,

Pb

(

NO

3

)

2

, and sodium bromide,

NaBr

, are soluble in an aqueous solution, which means that they dissociate completely to form cations and anions when dissolved in water.

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