Respuesta :
The mass of, [tex]Cu_2S[/tex], compound formed is 77.9g
62 grams of copper reacted with 32grams of sulfur to form copper sulfide.
[tex]Cu + S_2 \rightarrow CuS_2[/tex]
stoichiometry of Cu to S is 2:1
We need to find the limiting reactant
Molar mass of copper = 63.5 g/mol
Molar mass of Sulfur = 32 g/mol
Number of moles of Copper = [tex]\dfrac{mass} {molar mass } = 0.99mole[/tex]
Number of moles of Sulfur = [tex]\dfrac{mass} {molar mass} = \dfrac{32g} {32g/mol} = 1 mole[/tex]
Since copper have lesser number of moles, therefore the limiting reagent is copper so the amount of product formed depends on amount of Cu present
stoichiometry of Copper to [tex]Cu_2S[/tex] is 2:1
0.99 mol of Copper forms = [tex]\dfrac{0.99} {2}[/tex] = 0.49 mol of [tex]Cu_2S[/tex]
Mass of [tex]Cu_2S[/tex] produced = Number of moles [tex]\times[/tex] Molar mass
Mass of [tex]Cu_2S[/tex] produced = 0.49 mol [tex]\times[/tex] 159 g/mol = 77.9g
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