An ideal gas at 20 degrees centigrade has a volume of 12 liters and a pressure of 15 atmospheres. Its temperature is raised to 35 degrees centigrade and compressed to a volume of 8.5 liters. Calculate the final pressure of the gas. (2 pts.)

Respuesta :

P 15 atm

V₁ = 12x103 m3 -3 3 V₁ = 12x10 m" T₁ = 25°c T= 28815 K

P₁ = 1.52x10 Pa

Now, Finel quantities, T₂ = 35°C = 308.15 °K

V2= 851 = -3 3

Now

by ideal gas equation

P2Y2 T2

= PV, T2

1152 X106 x 12x16 3 x 308115 8,5×103 x 288,15 = Pa

=

21294×10 Pa

P₂ = 21264 Atm

final

pressure will be

21264 Adm.

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