The second 18.0 kg child must sit 2.33 m board to balance the seesaw.
(a) Under equlibrium condition, the net torque is constant
m1 g x1 = m2 g x2
30 kg ( 1.4) = 18 ( x2)
x2 = 2.33 m board.
(b) Since the seesaw is 3.0 m long the pivot point will be the center of the seesaw which is a 1.50 m board on the other side of the pivot.
As per calcualtion second child mist sit at a distance of 2.33 from the pivot point which means off the board this is unreasonable about the result.
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