It takes, on average, 6 minutes to do all the steps but the actual time can vary according to an exponential distribution with a standard deviation of 6 minutes. Assume students arrive on average every 6.6 minutes and their inter-arrival times are also exponentially distributed. What is the expected waiting time in this system according to the Kingman (PK) Formula

Respuesta :

The expected waiting time is 1.2 minute

According the statement

We know that the kingman formula is

[tex]{ E(W) = \left ( \frac{p}{1-p} \right )\cdot \left ( \frac{ C_{a}^{2}+ C_{s}^{2} }{2} \right ) \cdot \mu_{s} }[/tex]

According to statement the mean value μs is 6 min.

Here the value of P is 6/36 = 1/6

And the value of ca and cs is 1

Substitute the values in formula then

[tex]{ E(W) = \left ( \frac{0.17}{1-0.17} \right )\cdot \left ( \frac{ 1^{2}+ 1^{2} }{2} \right ) \cdot \m6} }[/tex]

[tex]{ E(W) = \left ( \frac{0.17}{0.83} \right )\cdot \left ( 1 ) \cdot \m6} }[/tex]

[tex]{ E(W) = \left ( 0.20} \right )\cdot \left ( 1 ) \cdot \m6} }[/tex]

[tex]{ E(W) = 1.22[/tex]

So, the expected waiting time is 1.2 minute

Learn more about PK FORMULA here https://brainly.com/question/2005046

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