Spiderman, whose mass is 80.0 kg, is dangling on the free end of a 12.0-m-long rope, the other end of which is fixed to a tree limb above. By repeatedly bending at the waist, he is able to get the rope in motion, eventually getting it to swing enough that he can reach a ledge when the rope makes a 60.08 angle with the vertical. How much work was done by the gravitational force on Spiderman in this maneuver

Respuesta :

4.719kJ is the work done by the gravitational force.

Given,

Mass of Spiderman, m = 80 kg

Acceleration due to gravity, g = 9.8[tex]m/s^{2}[/tex]

Formula used

F= mg

So, The force on Spiderman is= 80 × 9.8 = 784N

As Spiderman is dangling on the free end of a long rope, the other end of which is fixed to a tree limb above.

That's why only his vertical movement makes a difference in how much work gravity does.

So, we only consider the y coordinates here

As the rope is 12m long ,

y coordinate below the tree limb is –12m. (negative sign because the value is present below the origin.)

As it is given that the rope makes a 60.08° angle with the vertical.

So his final y coordinate is (–12.0m)cos60.08°

= -12×0.498 = -5.98m

Change in elevation (ΔS)=  –5.98m–(–12.0m)= 6.02m.

The work done by the gravity on Spiderman is:

W=FΔscosθ….. (1)

where, F = Force of gravity on Spiderman

ΔS = Change in the elevation

θ = angle between force and the displacement

Putting the values in equation (1)

W = 784 × 6.02 ×cos 180°

   = 784 × 6.02 × -1 = 4719.68 J = 4.719kJ

Hence, the work was done by the gravitational force on Spiderman in this maneuver is 4.719 kJ.

Learn more about Work done here https://brainly.com/question/23653951

#SPJ4