contestada

Multiply Conjugates Using the Product of Conjugates Pattern
In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern
329. (9c + 5)(9c − 5)

Respuesta :

Answer:

The product is the difference of squares is [tex]$\left(9c+5\right)\left(9c-5\right)=81{{c}^2}-25$[/tex]

Step-by-step explanation:

Explanation

  • The given expression is (9 c+5)(9 c-5).
  • We have to multiply the given expression.
  • Square the first term 9c. Square the last term 5 .

[tex]$\begin{aligned}&(9 c+5)(9 c-5)=(9 c)^{2}-(5)^{2} \\&(9 c+5)(9 c-5)=81 c^{2}-25\end{aligned}$[/tex]

Otras preguntas