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Try It #3
There is a straight road leading from the town of Timpson to Ashburn 60 miles east and 12 miles north. Partway down the road, it junctions with a second road, perpendicular to the first, leading to the town of Garrison. If the town of Garrison is located 22 miles directly east of the town of Timpson, how far is the road junction from Timpson?

Respuesta :

ogorwyne

The distance of the road junction form Timpson is given as 21.57 miles.

We have to solve this using the Pythagoras theorem method

We have AT = [tex]\sqrt{TN^{2}+AN^{2} }[/tex]

√60² + 12² = 12√26

∠TMG = LN = 90 degrees

Therefore we have the system

[tex]\frac{TM}{60} = \frac{22}{12\sqrt{26} }[/tex]

When we cross multiply we would have to solve for TM

TM = 21.57 miles

Hence the distance of the road junction form Timpson is given as 21.57 miles.

Read more on distance here:

https://brainly.com/question/17273444

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