Respuesta :

Based on the mole ratio of the reaction:

  • Moles of aluminum carbonate produced = 0.00765 moles
  • Moles of sodium nitrate produced = 0.02295 moles.

What is the mole ratio of the reaction between aluminum nitrate and sodium carbonate?

The mole ratio of the reaction is given by the equation of reaction as follows:

[tex]2\:Al(NO_{3})_{3} + 3\:Na_{2}CO_{3} \rightarrow Al_{2}(CO_{3})_{3} + 3\:NaNO_{3}[/tex]

The mole ratio of the products and reactants are used to determine the amount of product

Moles of aluminum nitrate reacting = 141/1000 * 1.2 M = 0.1692 moles

Moles of sodium carbonate reacting = 85/1000 * 0.27 = 0.02295 moles

Based on the mole ratio, sodium carbonate is the limiting reactant.

Moles of aluminum carbonate produced = 0.02295 * 1/3 = 0.00765 moles

Moles of sodium nitrate produced = 0.02295 * 3/3 = 0.02295 moles.

Therefore, the moles of the products aluminum carbonate  and sodium nitrate produced is determined from the mole ratio of the reaction.

Learn more about mole ratio at: https://brainly.com/question/19099163

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