Respuesta :
The sample size which will produce sample proportion of 0.3 and 95% confidence interval is 36.
Given sample proportion of 0.3, confidence level 95%.
A confidence interval of proportions is given by:
π±z[tex]\sqrt{}[/tex]π(1-π)/n
In which :
π is the sample proportion,
z is the critical value
n is the sample size.
Margin of error=z[tex]\sqrt{}[/tex]π(1-π)/n
z value for confidence level of 95% is 1.96
Margin of error=1.96[tex]\sqrt{0.3*0.7/n}[/tex]
The widest interval has the highest margin of error, since the margin of error and since the margin of error is inversely proportional to the sample size , a lower sample size generates a higher margin of error.
Hence sample size which is correct is 36.
Learn more about margin of error at https://brainly.com/question/24289590
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Question is incomplete as it also includes options like:
a)46
b)68
c)56
d)36.
