Calculus help please 10 points for 18&19
thanks!
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First function - The function is not continous on [0, 5] because h(5) is not defined.
Second function - There are no discontinuities.
In this problem we have two functions, whose continuity has to be checked. The first equation is a rational function and the second one is a polynomic function. There is a discontinuity in a function f at a given point if and only if the function evaluated at such point does not exist.
The discontinuities of rational functions are those x-values such that the denominator equals zero. The first function is defined for the interval [0, 5] and it is continuous if the function exists for all value of the interval. Thus:
5 - x = 0
x = 5
The rational function has a discontinuity at x = 5. The function is not continous on [0, 5] because h(5) is not defined. (Correct choice: C)
In accordance to algebra, polynomic functions are continuous as there exist a result for all value of x. There are no discontinuities.
To learn more on discontinuities: https://brainly.com/question/12644479
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