a)The velocity of the knife relative to the ship when it hits the deck of the ship will be 14.00 m/sec.
b)The velocity of the knife relative to a stationary observer on shore is 14.10 m/sec
c)The position at which the knife hits the deck is 82.8°.
The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is;
The velocity of the knife relative to the ship when it hits the deck of the ship is;
v=√2gh
v=√2×9.81 ×10.0 m
v=14.00 m/sec
b)
The velocity of the knife relative to a stationary observer on shore is found as;
v₁₂ = √[(14.00)²+(1.74)²]
v₁₂=14.10 m/sec
c)
The position at which the knife hits the deck is;
[tex]\rm \theta = tan^{-1}\frac{14.00}{1.75} \\\\ \theta = 82.8 ^ 0[/tex]
Hence, the velocity of the knife relative to the ship, the velocity of the knife relative to a stationary observer on shore, and the position at which the knife hits the deck will be 14.00 m/sec,14.10 m/sec, and 82.8° respectively.
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