Respuesta :
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 101kpa =0.996792 atm
V= ?
R=[tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=25 +273 =298 K
Moles =?
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{185 g }{308.6}[/tex]
Moles =0.56
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]0.56= \frac{0.996792\;atm\; X \; V }{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
13.73 L =V
13.73 L of oxygen gas were used up if 185 g of wax [tex]C_{22}H_{44}[/tex] burns.
Learn more about the ideal gas here:
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