Respuesta :
(a)The position at the end of 1 s of a point originally at the top of the wheel will be 9.425 radians.
(b)The magnitude and the direction of the acceleration at the end of 1 s will be 1.885 m/sec² clockwise.
What is angular acceleration?
Angular acceleration is defined as the pace of change of angular velocity concerning time.
Given data;
Diameter of the wheel,d = 0.2 m
Initial velocity,ω₀ = 0
Angular acceleration,α = c
n = 900 rev min¹
ω = 94.2478 rad /sec
Time of rolling,t = 5 s
From Newton's first equation of motion;
ω = ω₀ + αt
94.2478 rad /sec = 0 + α(5 sec)
α = 18.85 rad/sec²
The position at the end of 1 s of a point is found as;
Θ = ω₀t+1/2(αt²)
Θ = 0+1/2[(18.85 rad/sec²) × (1 sec)²]
Θ = 9.425 radian
The magnitude and the direction of the acceleration at the end of 1 s are found as;
a = αr
a= 18.85 rad/sec² × 0.1 m
a = 1.885 m/sec²
Hence the position at the end of 1 s and magnitude and the direction of the acceleration at the end of 1 s will be 18.85 rad/sec²and the magnitude and the direction of the acceleration at the end of 1 s will be 1.885 m/sec² clockwise.
To learn more about angular acceleration refer to the link;
https://brainly.com/question/408236
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