Respuesta :
Answer:
the point of intersection is (-1 , -2)
Step-by-step explanation:
[tex]\begin{cases}x-y=1&(1)\\ 3x-y=-1&(2)\end{cases}[/tex]
(2) - (1) ⇒ (3x - y) - (x - y) = (-1) - 1
⇒ 3x - y - x + y = -2
⇒ 3x - x = -2
⇒ 2x = -2
⇒ x = -1
……………………………
Now ,we can determine the value of y
by substituting x by its value -1 in the first equation (1) :
(1) x - y = 1 ⇒-1 - y = 1 ⇒ -y = 2 ⇒ y = -2
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Conclusion:
x = -1
y = -2
Then ,the point of intersection of the graphs is (-1 , -2)
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Hello !
[tex]\begin{cases} x - y &=1 \\ 3x-y &= - 1 \end{cases} \\\Leftrightarrow \begin{cases} x =y + 1 \\ 3x-y = - 1 \: \: \: \: \: (a)\end{cases} [/tex]
We replace x by y+1 in (a) :
[tex]3(y + 1) - y = - 1 \\ 3y + 3 - y = - 1 \\ 2y = - 4 \\ y = \frac{ - 4}{2} = - 2[/tex]
Now we replace x by -1 in the first equation.
[tex]x + 2 = 1 \\ x = -1[/tex]
The point of intersection is (-1;-2).
Have a nice day