Respuesta :

Answer:

No solutions

Step-by-step explanation:

First  ADD  4 /(X+4)   to both sides of the equation to get

( x+4)/ (x+ 4)  = 3

1 = 3 ????    There are no solutions

[tex]\dfrac{x}{x+4}=3-\dfrac{4}{x+4}\qquad(x\not=-4)\\\\x=3(x+4)-4\\x=3x+12-4\\2x=-8\\x=-4[/tex]

Which contradicts initial assumption, therefore [tex]x\in\emptyset[/tex].