Answer:
18 square feet.
Step-by-step explanation:
Area of trapezoid:
a = 6 ft
b = 3 ft
h = 4 ft
a & b are the length of the parallel lines. h is the height between the parallel lines.
[tex]\sf \boxed{\text{\bf Area of trapezoid =$ \dfrac{(a+b)*h}{2}$}}[/tex]
[tex]\sf =\dfrac{(6+3)*4}{2}\\\\=\dfrac{9*4}{2}\\\\= 9 * 2\\\\= 18 \ ft^2[/tex]
