Use matrix method to find the point of intersection between the lines:

5x+3y-35=0 and 3x-4y=-8

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Globule Globule · Answer 1 · 2022-07-10T10:03:27+02:00

Hello !

[tex]\begin{cases} 5x+3y - 35&=0 \\ 3x - 4y &= - 8 \end{cases}[/tex]

[tex]\Leftrightarrow\begin{cases} 5x+3y &=35 \\ 3x - 4y &= - 8 \end{cases}[/tex]

[tex]\Leftrightarrow AX = B [/tex]

With

[tex]A=\left[\begin{array}{ccc}5&3\\3& - 4\end{array}\right] [/tex]

[tex]X=\left[\begin{array}{ccc}x\\y\\\end{array}\right] [/tex]

[tex]B=\left[\begin{array}{ccc}35\\ - 8\\\end{array}\right] [/tex]

The solution is given by [tex]X=A^{-1}B[/tex].

[tex]X= {\left[\begin{array}{ccc}5&3\\3& - 4\end{array}\right] }^{ - 1} \left[\begin{array}{ccc}35\\ - 8\\\end{array}\right] [/tex]

[tex]X=\left[\begin{array}{ccc}4\\ 5\\\end{array}\right] [/tex]

The point of intersection between the lines is (4;5).

Have a nice day

devishri1977 devishri1977 · Answer 2 · 2022-07-11T16:57:18+02:00

Answer:

Point of intersection (4,5)

Step-by-step explanation:

5x + 3y - 35 = 0

3x - 4y = -8

⇒ 5x + 3y = 35

3x - 4y = -8

Matrix A will be formed by the coefficient of x and y. Matrix B will be formed by the constants.

[tex]\sf A = \left[\begin{array}{cc}5&3\\3&-4\end{array}\right][/tex]

[tex]\sf B = \left[\begin{array}{c}35&-8\end{array}\right][/tex]

AX = B

[tex]\sf X =A^{-1}B[/tex]

[tex]Now ,\ we \ have \ to \ find \ A^{-1}[/tex],

Find the workout in the document attached.