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The electrode potential of metals are:
MG2+ + 2e- -------------> Mg E* -2.71 V
Ag -----------> ag+ + 1e- E* -0.8 V

Cell potential (emf) of the cell formed by these two will be:
A. + 3.51 v B. -3.51 v
C. + 1.91 v D. – 1.91 v

Respuesta :

shristiparmar1221

The cell potential of the cell formed by these two reaction will be -1.91 v Hence, Option (C) is Correct.

What is cell potential ?

The cell potential, (Ecell), is the measure of the potential difference between two half cells in an electrochemical cell.

Given ;

  • Reduction potential of first half cell reaction = -2.71 v
  • Reduction potential of second half cell reaction = 0.8 v

To Find :

  • Cell potential of the cell formed by these two reaction

Solution :

  • The cell potential of the cell formed by these two reaction will be -1.91 v

The reaction MG²⁺ + 2e- -------------> Mg is a reduction reaction while the reaction Ag ---> Ag + 1e⁻ is an oxidation reaction.

Second reaction is oxidation reaction so to convert it into reduction reaction we will change the sign of its electrode potential Hence, reduction potential of second half cell is 0.8 v

Now, to find the cell potential of the cell formed by these two reaction we will add the two half reactions and we get,

-2.71 + 0.8 = -1.91

Hence the cell potential of the cell formed by the given reaction is -1.91 v.Therefore, Option (C) is Correct.

Learn more about cell potential here ;

https://brainly.in/question/5943120

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