The question is incomplete hence, I gave you a similar question that will enable you to understand how to treat Linear Equations with Decimals.
This is best exemplified by the example below:
[tex]\left\{ \begin{array}{cl}0.2x-0.3y = 1.3 \\0.5x + 0.2y= 2.3\end{array} \right.[/tex]
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Solution
Step 1 - Remove all decimals by multiplying equation 1 and 2 by 10. This gives us:
[tex]\left\{ \begin{array}{cl}2x-3y = 13 \\5x + 2y= 23\end{array} \right.[/tex]
Now we have an equation without decimals.
Step 2 - we proceed to solve by elimination.
Assuming:
2x - 3y = 13 ............is Equation 3; and
5x -2y = 23 ............. is Equation 4;
Lets multiply equation 3 by 2; and equation 4 by 3. This gives us
⇒ 4x - 6y = 26 ...............5
15 x + 6y = 69..............6
step 3 - Add equation 5 and 6 to eliminate y.
4x - 6y = 26
15 x + 6y = 69
19x = 95
solving for x
= 95/19
x = 5
Step 4 - Substitute x into any of the equations to find the value of Y
Using equation 5, we have:
4x - 6y = 26
⇒ 4(5) - 6y = 26
⇒ 20 - 6y = 26
⇒ -6y = 26-20
⇒ y = 6/-6
∴ y = -1
In summary, x = 5; y = -1
Learn more about Linear systems with decimals at:
https://brainly.com/question/10566339
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