Kevlar epoxy is a material used on the NASA space shuttles. Strands of this epoxy were tested at the 90% breaking strength. The following data represent time to failure (in hours) for a random sample of 50 epoxy strands. Let x be a random variable representing time to failure (in hours) at 90% breaking strength.
0.52 1.80 1.52 2.05 1.03 1.18 0.80 1.33 1.29 1.14
3.34 1.54 0.08 0.12 0.60 0.72 0.92 1.05 1.43 3.04
1.81 2.17 0.63 0.56 0.03 0.09 0.18 0.34 1.51 1.45
1.52 0.19 1.55 0.02 0.07 0.65 0.40 0.24 1.51 1.45
1.60 1.80 4.69 0.08 7.89 1.58 1.62 0.03 0.23 0.72
(a) Find the range.
(b) Use a calculator to calculate ?x and ?x2.
(c) Use the results of part (b) to compute the sample mean, variance, and standard deviation for the time to failure.
(d) Use the results of part (c) to compute the coefficient of variation.
What does this number say about time to failure?
1) The standard deviation of the time to failure is just slightly smaller than the average time.
2) The coefficient of variation says nothing about time to failure.
3) The standard deviation of the time to failure is just slightly larger than the average time.
4) The standard deviation is equal to the average.
Why does a small CV indicate more consistent data, whereas a larger CV indicates less consistent data? Explain.
1) A small CV indicates more consistent data because the value of s in the numerator is smaller.
2) A small CV indicates more consistent data because the value of s in the numerator is larger.

Respuesta :

The range of the data set based on the information will be 7.88.

How to calculate the range?

The range is the difference between the highest and lowest values in the data set. The range will be:

= maximum-minimum

= 7.89-0.01

=7.88

Σx=sum of all values = 62.14

Σx² =sum of square of all values = 164.3834

The sample mean, variance, and standard deviation for the time to failure are 1.2428, 1.7431, and 1.3203.

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