Answer: 1/6
Step-by-step explanation:
Probability of getting heads or tail is:
P (H) = P(T) = 1/2
The probability of getting any number on the die is:
P (1) = P (2) = P(3) = P (4) = P (5) = P (6) = 1/6
The probability of getting a tail on the coin and a number less than 3 on the die is:
[tex]P($Tails and a number less than 3$)=P($Tails$) \times P$(A number less than 3)$\begin{aligned}&=\frac{1}{2} \times[P(1)+P(2)] \\&=\frac{1}{2} \times\left[\frac{1}{6}+\frac{1}{6}\right] \\&=\frac{1}{6}\end{aligned}$[/tex]
Therefore the required of getting tails and a number less than 3 is 1/6
