What would the spring constant (k) need to be for Spring A, if it needed to store as much
elastic potential energy when stretched 0.5m as Spring B? Spring B has a spring constant
of 0.67 when stretched 0.8m?

Respuesta :

The spring constant needed for spring A to store as much potential energy as B is 1.72

How to determine the energy of spring B

  • Spring constant (K) = 0.67 N/m
  • Extention (e) = 0.8 m
  • Energy (E) =?

E = ½Ke²

E = ½ × 0.67 × 0.8²

E = 0.335 × 0.64

E = 0.2144 J

How to determine the spring constant of spring A

  • Energy of spring B = 0.2144 J
  • Energy of spring A = Energy of B = 0.2144 J
  • Extention (e) = 0.5 m
  • Spring constant (K) =?

E = ½Ke²

0.2144 = ½ × K × 0.5²

0.2144 = ½ × K × 0.25

0.2144 = K × 0.125

Divide both side by 0.125

K = 0.2144 / 0.125

K = 1.72

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