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Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)
to ethanol (C₂H6O) and CO₂.
C6H12O6(s)
AH = -16 kcal/mol
2 C₂H6O()+2 CO₂(g)
ethanol
glucose
How many kilocalories of energy are released from 49.0 g of glucose?
_____kcal of energy released
Report answer to TWO significant figures.

Respuesta :

Eduard22sly

The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

C₆H₁₂O₆ →2C₂H₆O + 2CO₂  ΔH = -16 kcal/mol

From the balanced equation above,

1 mole of glucose released -16 kcal of energy

Therefore,

0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal

Thus, -4.4 Kcal were released from the reaction

Learn more about stoichiometry:

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