What values for theta (0≤theta≤2π) satisfy the equation?
Equation: 3 sin theta = sin theta - √3
Plss help!
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The values for θ (0 ≤ θ ≤ 2π) that satisfy the equation are; D: θ = π/3, 5π/3
We are given the trigonometric equation;
3 sin θ = sin θ - √3
Rearranging this gives;
sin θ - 3 sin θ = √3
(1 - 3) sin θ = √3
-2sin θ = √3
sin θ = -(√3)/2
θ = sin⁻¹-(√3)/2
θ = π/3, 5π/3
Read more about Trigonometric Equations at; https://brainly.com/question/24349828
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