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Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?
y = one-fifth x squared + six-fifths x + eleven-tenths
y = 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot
Negative 5 y minus 4 = negative (x + 3) squared minus one-half
y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Respuesta :

abidemiokin

The inverse of the given function is y = √5x + 7/2 - 3

Inverse of a function

Given the function expressed below;

5y + 4 = (x+3)² +1/2

5y = (x+3)² - 7/2

y = 1/5(x+3)² - 7/10

Replace y as x

x = 1/5(y+3)² - 7/10

Make y the subject of the formula

5x = (y+3)²- 7/2

(y+3)² = 5x + 7/2

y+3 = √5x + 7/2

y = √5x + 7/2 - 3

Hence the inverse of the given function is y = √5x + 7/2 - 3

learn more on inverse of a function here: https://brainly.com/question/3831584

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