The data is consistent with the combustion of carbon monoxide to carbon dioxide.
Molar mass of CO = 12 + 16 = 28 g/mol
Percentage O in CO = 16/28 x 100 = 57.1%
Molar mass of [tex]CO_2[/tex] = 12 +32 = 44 g/mol
Percentage O in [tex]CO_2[/tex] = 32/44 x 100 = 72.7%
Thus, the data is consistent with the equation:
[tex]2CO + O_2 --- > 2CO_2[/tex]
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