When an oxide of carbon containing 57.1% oxygen is burnt in the air the percentage of oxygen joined to the carbon increases to 72.7%. Show that this data is consistent with the combustion of carbon monoxide to carbon dioxide.

Respuesta :

Oseni

The data is consistent with the combustion of carbon monoxide to carbon dioxide.

Stoichiometric calculation

Molar mass of CO = 12 + 16 = 28 g/mol

Percentage O in CO = 16/28 x 100 = 57.1%

Molar mass of [tex]CO_2[/tex] = 12 +32 = 44 g/mol

Percentage O in  [tex]CO_2[/tex] = 32/44 x 100 = 72.7%

Thus, the data is consistent with the equation:

[tex]2CO + O_2 --- > 2CO_2[/tex]

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