Under the assumption of uniform motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.
How to calculate the distance taken by traveler before braking
According to this question, the vehicle travels at constant velocity before the traveler hit the brakes. The distance traveled (s), in feet, is equal to the product of velocity (v), in feet per second, and time (t), in seconds:
s = v · t (1)
If we know that v = 40 ft/s and t = 0.5 s, then the traveled distance of the vehicle is:
s = (40 ft/s) · (0.5 s)
s = 20 ft
Under the assumption of uniform motion, the traveller will travel a distance of 20 feet before slowing down the vehicle to less than 40 miles per second.
To learn more on uniform motion: https://brainly.com/question/118814
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