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(b) Figure 3 shows a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three forces acting on it shown in Figure 3. A applied 0.6 m 0.93 force (F) wheelbarrow 1.5 m → Figure 3 (i) Identify the nature and point of action of the third force acting on the wheelbarrow. Write down an equation showing the relationship between the THREE forces.​

Respuesta :

An equation showing the relationship between the THREE forces is R -W +F= 0

What is moment of force?

The equal and opposite force acting at a point from the axis of rotation is called the moment of force.

M = F x r

Given is a wheelbarrow and stones with a total mass of 43 kg. The wheelbarrow is in equilibrium with two of the three forces acting on it

Taking moment about the wheel, we get

-43x 9.81 x 0.6 + F x 1.5 =0

F = 43 x 0.6/1.5

F = 168.732 N (upward force)

Summation of forces in y direction is zero.

R -W +F= 0

Where, R is the normal force, W is the Weight force and F is the applied force.

Thus, this is the equation representing all the three forces acting on wheelbarrow.

Learn more about moment of force.

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