Answer:
Solve for x , 1x − 2+1x + 2=4(x − 2)(x + 2) .
1x − 2+1x + 2=4(x − 2)(x + 2)
(x − 2)(x + 2)(x − 2)+(x − 2)(x + 2)(x + 2)=4(x − 2)(x + 2)(x − 2)(x + 2)
(x−2)+(x+2)=4
2x=4
x=2
But 2 is excluded from the domain of the original equation because it would make the denominator of one of the fractions zero--and division by zero is not allowed! . Therefore, it cannot be a root of the original equation. So, 2 is an extraneous solution. So, the equation has no solutions.
Step-by-step explanation: