The displacement is 18.03 steps, and the direction is 47.25°
We know that displacement is the difference between the final position and the initial position.
We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.
First, the student moves 8 steps east, so she is at:
(0 + 8, 0)
Then she moves 6 steps northeast, so the new position is:
(6*cos(45°) + 8, 6*cos(45°))
Finally, she moves 9 steps due north, so we have:
(6*cos(45°) + 8, 6*cos(45°) + 9)
Then the final position is:
(12.24, 13.24)
So the displacement is:
D = (12.24, 13.24) - (0, 0) = (12.24, 13.24)
The magnitude of the displacement is:
[tex]|D| = \sqrt{12.24^2 + 13.24^2} = 18.03[/tex]
So the magnitude is 18.03 steps.
And the direction is given by the arctangent of the quotient between the y-component and the x-component:
[tex]\theta = Arctg(13.24/12.24) = 47.25 \°[/tex]
If you want to learn more about displacements:
https://brainly.com/question/4931057
#SPJ1
