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[tex]\diamond\large\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond[/tex]
What is the equation of the line that passes through the point (2, 5) and has a slope of 5?
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond[/tex]
First let's write the equation of the line in point-slope form:-
[tex]\sf{y-y_1=m(x-x_1)}[/tex]
Substitute 5 for y₁, 5 for m and 2 for x₁:-
[tex]\sf{y-5=5(x-2)}[/tex]
That's the equation of the line in Point-slope form.
Now let's convert it into slope-intercept:-
[tex]\sf{y-5=5x-10}[/tex]
Adding 5 to both sides results in our slope intercept equation, which looks like this:-
[tex]\dashrightarrow\bigstar\boxed{\boxed{\bold{\underline{y=5x-5}}}}\bigstar\dashleftarrow[/tex]
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