Respuesta :

                - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\diamond\large\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond[/tex]

             What is the equation of the line that passes through the point  (2, 5) and has a slope of 5?

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond[/tex]

First let's write the equation of the line in point-slope form:-

[tex]\sf{y-y_1=m(x-x_1)}[/tex]

Substitute 5 for y₁, 5 for m and 2 for x₁:-

[tex]\sf{y-5=5(x-2)}[/tex]

That's the equation of the line in Point-slope form.

Now let's convert it into slope-intercept:-

[tex]\sf{y-5=5x-10}[/tex]

Adding 5 to both sides results in our slope intercept equation, which looks like this:-

[tex]\dashrightarrow\bigstar\boxed{\boxed{\bold{\underline{y=5x-5}}}}\bigstar\dashleftarrow[/tex]

Good luck.

              - - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - -