The required number of grams of magnesium to make 0.40 Liters of Hydrogen gas at STP is 0.43 grams.
What is ideal gas equation?
Ideal gas equation gives idea about the behavior of gas at different condition & represented as:
PV = nRT, where
- P = standard pressure = 1atm
- V = volume = 0.4 L
- n = moles = ?
- R = universal gas constant = 0.082 L.atm / K.mol
- T = standard temperature = 273.15K
On putting values, we get moles as:
n = (1)(0.4) / (0.082)(273.15) = 0.0178 mol
Given chemical reaction is:
Mg + 2HCl → MgCl₂+ H₂
From the stoichiometry of the reaction:
0.0178 moles of H₂ = produced by the reaction 0.0178 moles of Mg
Mass of Mg = (0.0178mol)(24.3g/mol) = 0.43g
Hence required mass of magnesium is 0.43g.
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