[tex]\sf\large \green{\underbrace{\red{Answer⋆}}}:[/tex]
[A] Right option is C
[B] 11.55
Step-by-step explanation:
[tex] \sf \tan A{ \degree} = \frac{Perpendicular}{Base} [/tex]
- here perpendicular is 20
- and base is x
[tex] \sf \tan 60{ \degree} = \frac{20}{x} \\ \sf x = \frac{20}{ \tan60{ \degree}} [/tex]
now we need to find value of x
tan 60° = √3
[tex] \sf x = \frac{20}{ \sqrt{3} } [/tex]
first we need to rationalize by multiplying √3 in numerator and denominator
[tex] \sf x = \frac{20 \sqrt{3} }{3} \\ \sf x = \frac{34.64}{3} \\ \sf x = 11.55[/tex]
