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A cricket bowler bowls a cricket ball with a perfectly straight arm, accelerating their arm until they achieve an angular velocity of 2400°/s just prior to releasing the cricket ball. Taking the shoulder joint as the axis of rotation, discuss how the more proximal regions of the arm e.g., the elbow area, will differ from the more distal points of the arm e.g., the hand/ball, in terms of angular displacement, angular velocity, and angular acceleration, as well as in terms of linear displacement, velocity, and acceleration?

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onyebuchinnaji

The force applied on the hand/ball is lesser than the force applied on the arm, causing a lesser angular acceleration, velocity and displacement of the hand/ball.

Conservation of angular momentum

The angular acceleration of the ball is determined from the principle of conservation of angular momentum.

τ = Fr

Fr = Iα

α = Fr/I

F = Iα/r

where;

  • F is the force applied to the ball
  • r is perpendicular distance
  • I is moment of inertia of the ball
  • α is angular acceleration of the ball

From the formula above, the greater the distance from axis of rotation, the lesser the applied force.

The arm is closer to the axis rotation than the hand/ball.

The force applied on the hand/ball is lesser than the force applied on the arm.

  • When the applied force is small, the angular acceleration will be small.
  • When the angular acceleration is small, the angular velocity will be small.
  • When the angular velocity is small, the angular displacement will be small.

Similar effect will happen to linear displacement, velocity, and acceleration.

Learn more about angular momentum here: https://brainly.com/question/7538238

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